|
|
| Line 1: |
Line 1: |
| | + | == Unit abbreviations<br> == |
| | + | |
| | + | {| cellspacing="1" cellpadding="1" border="0" align="left" style="width: 399px; height: 132px;" |
| | + | |- |
| | + | | m = metre = 3.28 ft.<br> |
| | + | | HP = horsepower<br> |
| | + | |- |
| | + | | s = second<br> |
| | + | | J = Joule<br> |
| | + | |- |
| | + | | h = hour<br> |
| | + | | cal = calorie<br> |
| | + | |- |
| | + | | N = Newton<br> |
| | + | | toe = tonnes of oil equivalent<br> |
| | + | |- |
| | + | | W = Watt<br> |
| | + | | Hz= Hertz (cycles per second)<br> |
| | + | |} |
| | + | |
| | + | |
| | + | |
| | + | |
| | + | |
| | + | |
| | + | |
| | + | |
| | + | |
| | + | |
| | + | |
| | + | |
| | + | |
| | + | |
| | + | |
| | == Wind Power == | | == Wind Power == |
| | | | |
| Line 19: |
Line 53: |
| | <math>P=\dot{E}=\frac{1}{2}\dot{m}v^2=\frac{1}{2}\rho A v^3</math> | | <math>P=\dot{E}=\frac{1}{2}\dot{m}v^2=\frac{1}{2}\rho A v^3</math> |
| | | | |
| − | | + | <br> |
| | | | |
| | The power of a wind-stream is transformed into mechanical energy by a wind turbine through slowing down the moving air-mass which is crossing the rotor area. For a complete extraction of power the air-mass would have to be stopped completely, leaving no space for the following air-masses. | | The power of a wind-stream is transformed into mechanical energy by a wind turbine through slowing down the moving air-mass which is crossing the rotor area. For a complete extraction of power the air-mass would have to be stopped completely, leaving no space for the following air-masses. |
Revision as of 16:10, 17 May 2011
Unit abbreviations
m = metre = 3.28 ft.
|
HP = horsepower
|
s = second
|
J = Joule
|
h = hour
|
cal = calorie
|
N = Newton
|
toe = tonnes of oil equivalent
|
W = Watt
|
Hz= Hertz (cycles per second)
|
Wind Power
The power P of a wind-stream, crossing an area A with velocity v is given by
Failed to parse (PNG conversion failed; check for correct installation of latex and dvipng (or dvips + gs + convert)): P=\frac{1}{2}\rho A v^3
It varies proportional to air density Failed to parse (PNG conversion failed; check for correct installation of latex and dvipng (or dvips + gs + convert)): \rho
, to the crossed area A and to the cube of wind velocity v.
The Power P is the kinetic energy
Failed to parse (PNG conversion failed; check for correct installation of latex and dvipng (or dvips + gs + convert)): E=\frac{1}{2}mv^2
of the air-mass m crossing the area A during a time interval
Failed to parse (PNG conversion failed; check for correct installation of latex and dvipng (or dvips + gs + convert)): \dot{m}=A \rho \frac{dx}{dt}=A\rho v
.
Because power is energy per time unit, combining the two equations leads back to the primary mentioned basic relationship of wind energy utilisation
Failed to parse (PNG conversion failed; check for correct installation of latex and dvipng (or dvips + gs + convert)): P=\dot{E}=\frac{1}{2}\dot{m}v^2=\frac{1}{2}\rho A v^3
The power of a wind-stream is transformed into mechanical energy by a wind turbine through slowing down the moving air-mass which is crossing the rotor area. For a complete extraction of power the air-mass would have to be stopped completely, leaving no space for the following air-masses.
